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Basile [38]
3 years ago
13

Well y’all thanks for helping me out

Mathematics
1 answer:
Yuri [45]3 years ago
7 0
Answer: 2 because F(5) complies with the 2nd function.
*Just follow the function the the number satisfies!!*
(WORK SHOWN BELOW)

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Which property is shown in the following statement?
dusya [7]

Answer:

Step-by-step explanation:

Identity property of multiplication:  Any number times 1 (unity) is the number itself.  7 times 1 is 7, the number with which we started.

7 0
3 years ago
Two posts that hold up a sign are parallel. M < 1 = 75° use the given measurements to find the value of x. I think it’s 19 bu
polet [3.4K]

The two posts are parallel lines. The ground is a transversal.

The angles measuring 4x and 75 are same side interior angles, so they are supplementary. Their measures add up to 180.

4x + 75 = 180

4x = 105

x = 26.25

4 0
3 years ago
Read 2 more answers
Help me find answer to this
Debora [2.8K]

Answer:

\angle B=41.81^\circ

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the triangle is called the hypotenuse and the other two sides are the legs.

The sine ratio relates the opposite side of an angle of the triangle with the hypotenuse:

\displaystyle \sin B=\frac{\text{opposite leg}}{\text{hypotenuse}}

Here, the opposite leg to angle B is the side CA=2, and the hypotenuse is the side AB=3, thus:

\displaystyle \sin \angle B=\frac{2}{3}=0.667

Calculating the inverse sine function:

\angle B=\arcsin (0.667)

\boxed{\angle B=41.81^\circ}

5 0
3 years ago
7/8 - 5/12 ayudaaa por favor es para mañana​
RUDIKE [14]
7/8 = 21/24
5/12 = 10/24

21/24-10/24 = 11/24
3 0
3 years ago
What is the total weekly pay for a person earning $9.00 an hour and working only 8 hours a day for 5 days?
melomori [17]
First you woyld find how many hours total he worked.
5 \times 8 = 40
Then take the number of hours and multiply by the pay earned per hour.
40 \times 9 = 360
They would make $360 per week.
6 0
3 years ago
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