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3 years ago

The center of a circle is located at (1, 3) , the point lies on (0, 1) what is the equation for the circle?

Mathematics

1 answer:

lesya692 [45]3 years ago

8 0

Answer: (x-1)^2 + (y-3)^2 = 5

Step-by-step explanation:

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Jami covered the lateral faces the

IgorLugansk [536]

Answer:

304

Step-by-step explanation:

find the area of each side, then add together

top and bottom are 10*8= 80 80*2= 160

front and back are 10*4=40 40*2=80

left and right sides are 8*4=32 32*2=64

160+80+64=304

5 0

2 years ago

Pls help me solve this question, also include step by step calculation ya. Thks

sp2606 [1]

$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

6 0

1 year ago

A car leaving a stop sign accelerates...what is the average speed of the car, in feet per second, equation d=1.1t^2 average spee

spayn [35]

Answer:

10.27 feet/sec.

Step-by-step explanation:

The distance traveled by the car, d in feet, is given by the function $d = 1.1t^{2}$ .......... (1), where t is the time in seconds.

So, at t= 2 sec, from equation (1) we get d = 1.1 × 4 = 4.4 feet.

Again, at t = 5 sec, we get d = 1.1 × 32 = 35.2 feet.

Now, average speed of the car from t = 2 sec. to t = 5 sec. will be give by

$\frac{\textrm {Total distance traveled}}{\textrm {Total time spent}}$

= $\frac{35.2 - 4.4}{5 - 2} = 10.27$ feet/sec. (Answer)

8 0

3 years ago

A number is 9 more than another number. Twice the sum of the two numbers is 10. Find the two numbers.

Brrunno [24]

Step-by-step explanation:

the formula can be;

X+9x=10

10x=10X=10/10=1

X=1+9(1)=1+9=10 Answer

4 0

3 years ago

The average human heart beats 1.15 \cdot 10^51.15⋅10 5 1, point, 15, dot, 10, start superscript, 5, end superscript times per da

andriy [413]

Answer:

$4.1975\cdot 10^{7}$

Step-by-step explanation:

We are told that the average human heart beats $1.15\cdot 10^{5}$ times per day and there are $3.65\cdot 10^{2}$ days in one year.

To find number of heart beats in one year we will multiply number of heart beats in one day by number of days in one year.

$1.15\cdot 10^{5}\times 3.65\cdot 10^{2}$

Now we will solve this problem using exponent properties.

$1.15 \times 3.65\cdot 10^{2+5}$

$1.15 \times 3.65\cdot 10^{7}$

$4.1975\cdot 10^{7}$

Our answer is in scientific notation we can represent it in standard form as $4.1975\cdot 10^{7}=4.1975*10000000=41975000$ times.

Therefore, average human heart beats in one year $4.1975\cdot 10^{7}$ or 41975000 times.

4 0

3 years ago

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