Answer:
i think it is AAAAA
Step-by-step explanation:
Sequence: 5/2, 5/4, 5/8, 5/16
a8=?
a1=5/2
a2=5/4
a3=5/8
a4=5/16
a2/a1=(5/4)/(5/2)=(5/4)*(2/5)=(5*2)/(4*5)=2/4=1/2
a3/a2=(5/8)/(5/4)=(5/8)*(4/5)=(5*4)/(8*5)=4/8=1/2
a4/a3=(5/16)/(5/8)=(5/16)*(8/5)=(5*8)/(16*5)=8/16=1/2
Ratio: r=a2/a1=a3/a2=a4/a3→r=1/2
an=a1*r^(n-1)
a1=5/2, r=1/2
an=(5/2)*(1/2)^(n-1)
an=(5/2)*[1^(n-1)/2^(n-1)]
an=(5/2)*[1/2^(n-1)]
an=(5*1)/[2*2^(n-1)]
an=5/2^(1+n-1)
an=5/2^n
n=8→a8=5/2^8
a8=5/256
Answers:
The formula for the general term or nth term for the sequence is an=5/2^n
a8=5/256
The inequality representation of the scenario is :
- 5m + 8c ≤ 25
- m = 1 and c = 1
- Number of mugs = m
- Cost per mug = $5
- Number of ground coffee = c
- Cost per ground coffee = $8
- Total amount to spend = $25
- (Number of mug × cost per mug) + (Number of ground coffee × cost of ground coffee) ≤total amount to spend
- Representing as an inequality : 5m + 8c ≤ 25
Combination of m and c that makes the inequality true :
- Using trial by error :
- m = 1 and c = 1
- 5(1) + 8(1) ≤ 25 ; 13 ≤ 25
Hence, m = 1 and c =1 are valid values for the expression.
Learn more : brainly.com/question/15748955
Answer:
138.16 in²
Step-by-step explanation:
The surface area SA of the cone is the sum of the base area B and the lateral area LA. The lateral area is half the product of the circumference and the slant height. The radius is half the diameter, so is 4 inches.
SA = B + LA
= πr² + (1/2)(2πrh) . . . . where h is the slant height
= (πr)(r +h)
Filling in the numbers, you have ...
SA = (3.14)(4 in)(4 in + 7 in) = 3.14×(44 in²) = 138.16 in²
Answer:
150,000*3^t for 6 hour increments (t=1 is 6 hours t=2 is 12)
150,000*3^(t/6) for hourly increments, each t is 1 hour.
Step-by-step explanation:
Well super simply you could do 150,000*3^t where t is measured in 6 hour intervals. so t=1 is 6 hours, and to get 1 hour you would need to do t=1/6
If you want t to be an increase of every hour you would just need to adjust, like I showed before 1/6 gets one hour so 150,000*3^(t/6) would be the model where every t increases by 1 hour.
