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3 years ago

If m 1 = (x + 60° and m 2= (5x - 64)°, what is m 3?

Mathematics

1 answer:

mamaluj [8]3 years ago

6 0

Answer:

m∠3 = 89°

Step-by-step explanation:

m∠1 = m∠2 because they are corresponding angles

x+60 = 5x-64

-4x = -124

x = 31

Find m∠2: 5(31) - 64 = 91

m∠3 = 180-91 = 89

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if the probability of an event is 26% what is the probability of its complement occurring? a. 100% b. 74% c. 26% or d. 24%

oksian1 [2.3K]

B. 74%
This is because the complement plus the original must equal 100%.
So...
100 - 26 = 74

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3 years ago

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If f(x) = 3 – x2, find f(-2).

Rufina [12.5K]

Answer:

f(- 2) = - 1

Step-by-step explanation:

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3 years ago

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2 years ago

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Suppose that the functions s and t are defined for all real numbers x as follows.

jeka94

Answer:

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

Step-by-step explanation:

Given functions are:

$s(x)= x+6\\t(x)= 4x^2$

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

$(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2$

Also we have to find

(s-t)(x) => we have to subtract function t from function s

$(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2$

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

$(s+t)(x) = s(x)+t(x)\\= x+6+4x^2$

Putting x = -3

$= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39$

Hence,

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

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2 years ago

PLEASE HELP EM THANKS Solve |c - 2| = 10.

yKpoI14uk [10]

$|c-2|=10\\
c-2=10 \vee c-2=-10\\
c=12 \vee c=-8$

4 0

2 years ago