(x+b/2a)^2-(b^2-4ac)/2a=0
Step 2:
Re-write the expression:
(x+b/2a)^2=(b^2-4ac)/4a^2
Step 3:
get the square root of both sides:
x+b/2a=sqrt[(b^2-4ac)/4a^2]
Step 4:
Simplifying we get:
x+b/2a=sqrt[b^2-4ac]/2a
Step 5
Make x the subject:
x=-b/2a+/-sqrt[b^2-4ac]/2a
Answer:
450
Step-by-step explanation:
I do mental math. I think this is right if not then I am sorry
What rectangular prims, what do you mean?!?
There are some grammar mistakes and therefore I can't read it properly to answer
Answer:
V=( 1/6 )* π * d³
Step-by-step explanation:
We khow that d= 2r⇒ r=d/2
- so r³= d³/8
- substitute r with d³/8
- V= (4/3)*π*(d³/8) = (4/3*8)*d³*π = (1/6 )* d³ *π
