Solve h for -9h-15=93

-In statistics and research, internal consistency is typically a measure based on the correlations between different items on the same test (or the same subscale on a larger test).

-It measures whether several items that propose to measure the same general construct produce similar scores.

8 0

3 years ago

Janice spent $54 to buy some pairs of pants. Each pair of pants cost the same whole dollar amount. How many pairs of pants could

Naddika [18.5K]

6 pants @ $ 9 each. Or 9 pants @ $ 6 each.

7 0

3 years ago

15x-7=2+12x I need help with this

Amanda [17]

Answer:

$\huge{ \boxed{ \bold{ \tt{x = 3}}}}$

<h3>♁ Question : Solve for x</h3>

15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>

$\text{15x - 7 = 2 + 12x}$

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛ $\sf{15x - 12x - 7 = 2}$

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛ $\sf{15x - 12x = 2 + 7}$

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛ $\sf{3x = 2 + 7}$

Add the numbers : 2 and 7

➛ $\sf{3x = 9}$

Divide both sides by 3

➛ $\sf{ \frac{3x}{3} = \frac{9}{3}}$

➛ $\boxed{ \bold{ \sf{x = 3}}}$

The value of x is $\boxed{ \sf{3}}$

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☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

$\sf{15x - 7 = 2 + 12x}$

$\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}$

$\dashrightarrow{ \sf{45 - 7 = 2 + 36}}$

$\dashrightarrow{ \sf{38 = 38}}$

L.H.S = R.H.S ( Hence , the value of x is 3 ).

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<h3>✒ Rules for solving an equation :</h3>

If an equation contains fractions ,multiply each term by the L.C.M of denominators.
Remove the brackets , if any.
Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
Simplify and get the single term on each side.
Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0

3 years ago