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Sedaia [141]
3 years ago
9

A high school basketball team has a budget specifically for towels and extra basketballs. A towel costs $4 and a basketball cost

s $22. Assume the budget is $350 and that 30 towels are needed for the team for the entire season. Use a standard form equation to determine how many basketballs may be purchased by the team.
Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0
First, you need to find the cost of the towels. If you need 30 towels and each towel is $4, you do 30*4.

The answer is $120

You then take the cost of towels (120) and subtract that from the budget (350) which leaves you with $230

Then you take $230 and divide it by $22 and that is the amount of basketballs that can be purchased.
Vsevolod [243]3 years ago
3 0

Answer:B

Step-by-step explanation:

Your budget is 350 and the 30 towels are mandatory to be purchased so 30 multiplied by 4 is 120 then you subtract that by the 350 you’ll get 230 which you then divide by 22 to see how many balls you can afford to purchase which is going to come out to 10.45 I rounded so since the 4 is not big enough I rounded down and stayed at 10.

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3 years ago
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You can look at the screenshot

Step-by-step explanation:

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4 years ago
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Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

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