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ss7ja [257]
3 years ago
14

If HI is not parallel to JK, what is m

Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

no coco concho kicks sub chick lux 8jzjxjfxktx

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Alan is conducting an experiment to determine whether a new medication is effective in reducing coughing. He finds 2,000 volunte
Leni [432]
You can conclude from this experiment that Alan's new medication is effective in reducing coughing from the the results of the treatment group. 
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3 years ago
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How much will fertilizer cost for a field 725 feet by 1,021 feet if one bag covers 10,000 square feet and costs $12.97 per bag?
zzz [600]

Answer:

$9600.72

Step-by-step explanation:

Area of the field = length × width

Length = 1,021 feet

Width= 725 feet

Area of the field = length × width

= 1,021 feet × 725 feet

= 740,225 square feet

One bag covers 1000 square feet

There are 740,225 square feet

Find the number of bags that will cover the total of 740,225 square feet

Total bags = 740,225 / 10000

=740.225 bags

A bag cost $12.97

Total cost of 740.225 bags= 740.225 × 12.97

= $9600. 71825

Approximately

$9600.72

5 0
3 years ago
Four friends are evenly dividing the cost of a meal at a pizza restaurant. They bought two large pizzas that cost $11 each, thre
marishachu [46]

Answer:

The answer is B. $11.50 each

Step-by-step explanation:

2 pizzas @ $11 each is $22

3 garlic bread orders @ $4 each is $12

2 pitchers of soda @ $6 each is $12

$22+$12+$12 = $46

4 friends are splitting it evenly.

$46 divided by 4 = $11.50


3 0
3 years ago
Mrs.Steffen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin
qaws [65]

Answer:

a. \\ 10! = 3628800;

b. \\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}

Step-by-step explanation:

We need here to apply the <em>Multiplication Principle </em>or the <em>Fundamental Principle of Counting</em> for each answer. Answer <em>b</em> needs an extra reasoning for being completed.

The <em>Multiplication Principle</em> states that if there are <em>n</em> ways of doing something and <em>m</em> ways of doing another thing, then there are <em>n</em> x <em>m</em> ways of doing both (<em>Rule of product</em> (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are <em>ten</em> students. When one is selected, there is no other way to select it again. So, <em>no repetition</em> is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is <em>why</em> the <em>Multiplication Principle</em> is important here.

This could be expressed mathematically using n!:

\\ n! = n * (n-1)! * (n-2)! *...* 2*1.

For instance, \\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.

So, for the case in question, the <em>ten</em> students can line up in:

\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800 ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy <em>only</em> the following places in forming the file:

\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th} <em>places</em>.

The members of Group 2 <em>only</em>:

\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th} <em>places</em>.

And the members of Group 3, the following <em>only</em> ones:

\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th} <em>places.</em>

Well, having into account these possible places for each member of G1, G2 and G3, there are: <em>10! ways</em> for lining up members of G1; <em>10! ways</em> for lining up members of G2 and, also, <em>10! ways</em> for lining up members of G3.

After using the <em>Multiplication Principle</em>, we have, thus:

\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19} <em>ways the students can line up to come in from recess</em>.

3 0
3 years ago
What are partial quotients of 145/5
djyliett [7]
Partial Quotient is the process of division that engage remainders on the first part of division.
The given situation:
 partial quotients to divide 145 by 5.
Let’s start solving,
=> 145 / 5
How many 5 are there in 145
=> 14 / 5 = 2, (2 x 5 = 10)
Bring down 4, then bring down 5
=> 45 / 5 = 9
Thus the answer is 29, there are 29 5s in 145.
5 0
3 years ago
Read 2 more answers
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