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Sergeu [11.5K]
3 years ago
8

What is the application of inverse matrix?

Mathematics
1 answer:
Mila [183]3 years ago
8 0

Answer:

The inverse matrix is used to solve the system of linear equations. It also tells us the consistent or inconsistent behaviour of the solution of equations.

Step-by-step explanation:

In real life,

  • Whereas in programming which is taught at the university, matrices and inverse matrices are used for coding and encrypting messages.
  • Matrices are also used in representing the real world data's like the population of people, infant mortality rate, etc.
  • They are best representation methods for plotting surveys.
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Help me ASAP I’ll mark you as a BL Question attached below
mojhsa [17]

Answer:

I think it might be A if not then its be

Step-by-step explanation:

sorry if its not right

8 0
3 years ago
A right triangle has one angle that measures 25º. What is the measure of the other acute<br> angle?
Leya [2.2K]

Answer:

65

Step-by-step explanation:

All the angles in a right triangle add up to 180

plug in what we know and we get

90+25+x=180

115+x=180

x=65

6 0
3 years ago
Alex made $28.74 for three hours of work at his job at the pet store . If he works a total of 40 hours in one week , how much mo
Alex

Answer:

$383.20

Step-by-step explanation:

28.74 ÷ 3 = $9.58 per hour

9.58 x 40 = 383.20

8 0
3 years ago
Given cosα = −3/5, 180 &lt; α &lt; 270, and sinβ = 12/13, 90 &lt; β &lt; 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

.

( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

6 0
3 years ago
Eight hundred thirty six thousand in standard form
balandron [24]
80036000.....................
8 0
3 years ago
Read 2 more answers
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