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DochEvi [55]
3 years ago
8

HEY YOU!! IT LOOKS LIKE I FORGOT THE QUESTION THE FIRST TIME ROUND!! Let's TRY AGAIN FOR THE BRAINLIEST SHALL WE!!

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

Step-by-step explanation:

g³ + g² - 12g ≠ 0

g(g² + g - 12) ≠ 0

g(g - 3)(g + 4) ≠ 0

g ≠ 0

g ≠ 3

g ≠ - 4

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If the third term in an arithmetic sequence is 7 and the common difference is -5, what is the value of the fourth termA.12B.2C.-
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7m2 + 3m + 4m2<br> What is the answer to this
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The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
OleMash [197]

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Compute x/y if
Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

{:\implies \quad \sf x+\dfrac{1}{y}=4}

Multiplying both sides by y will lead ;

{:\implies \quad \sf xy+1=4y}

{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}

Now, consider the second equation which is ;

{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}

Multiplying both sides by x will yield

{:\implies \quad \sf xy+1=\dfrac{x}{4}}

{:\implies \quad \sf xy=\dfrac{x}{4}-1}

{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}

As LHS of both equations (i) and (ii) are same, so equating both will yield;

{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}

Multiplying both sides by 4 will yield

{:\implies \quad \sf 16y-4=x-4}

{:\implies \quad \sf 16y=x}

Dividing both sides by y will yield :

{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}

<em>Hence, the required answer is 16</em>

5 0
2 years ago
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