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balu736 [363]
3 years ago
11

PLEASE CAN SOMEBODY HELP PLEASE I AM BEGGING YOU PLEASE

Mathematics
2 answers:
Artemon [7]3 years ago
6 0
I believe it is (15, -5)
rusak2 [61]3 years ago
5 0
(3,-1)? i believe that's what it would be
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Please help me with this question!
gavmur [86]
First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway   thus

\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}

solve for "x"
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4 years ago
Solve the system of equations:
Ahat [919]

Answer:

Step-by-step explanation:

z = 3

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Answer:

b

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is the answer to the question

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geniusboy [140]

Answer:

26

Step-by-step explanation:

4 0
3 years ago
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