Answer:
g o f = 
Step-by-step explanation:
Given


Required:
Find g o f
This is calculated as:


So:


![g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4](https://tex.z-dn.net/?f=g%28f%28x%29%29%20%3D%202%5B%2016x%5E2%20%2B%2016x%20%2B%204%29%5D%20-%204)


Answer:
2 < AB < 18
Step-by-step explanation:
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
Answer:
3.159 is answer for the solution
Answer:
<u>93°</u>
Step-by-step explanation:
According to angle sum property, all the internal angles of a triangle add up to 180 degrees.
=> 37 + 50 + ? = 180
=> ? = 180 - 87
=> ? = <u>93°</u>