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Komok [63]
3 years ago
10

HELP! will give brainliest if given right answers

Mathematics
2 answers:
disa [49]3 years ago
7 0

7.  tails, odd, 4

P(tails) = 1/2

P(odd) = 3/6 = 1/2

P(4) = 1/6

P(tails then odd then 4) = (1/2)×(1/2)×(1/6) = 1/24 ≈ 0.041666

Answer: 1/24, 4.2%

8.  tails, 6 or 1, 3

P(6 or 1) = 2/6 = 1/3

P(3) = 1/6

P( tails, 6 or 1, 3) = (1/2)(1/3)(1/6) = 1/36 ≈ 0.027777

Answer: 1/36, 2.8%

9.  heads, not 2, even

P(heads) = 1/2

P(not 2) = 5/6

P(even) = 1/2

P(heads, not 2, even) = (1/2)(5/6)(1/2) = 5/24 ≈ 0.208333

Answer: 5/24, 20.8%

mart [117]3 years ago
4 0

Answer:

7. 1/24  = 4.2%

8. 1/36  = 2.8%

9. 1/6 = 16.67%

<em>All percentages are rounded</em>

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Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4
Kay [80]

Answer:

<h2>c. x = -4 or x = 9</h2>

Step-by-step explanation:

\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}

Domain:

x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3

solution:

\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}

use <em>(a - b)(a + b) = a² - b²</em>

\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}

multiply both sides by (x - 3) ≠ 0

\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}

cancel (x - 3)

\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3

subtract \frac{4(x-3)}{x} from both sides

\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}

cross multiply

(4)(x)=(x+3)(-x+12)

use FOIL

4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36

subtract 4x from both sides

0=-x^2+12x-3x+36-4x

combine like terms

0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36

change the signs

x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0

The product is 0 if one of the factors is 0. Therefore:

x-9=0\ \vee\ x+4=0

x-9=0            <em>add 9 to both sides</em>

x=9\in D

x+4=0          <em>subtract 4 from both sides</em>

x=-4\in D

7 0
3 years ago
If both of these figures are drawn to scale, and the second drawing is the actual dimensions, how tall is the house?
Tanya [424]

Answer:

266.7 ft

Step-by-step explanation:

If.... 14 inches = 200 ft

Then the height of the house;

; (14/10.5) × 200

; 1.33333 × 200

Height of the house = 266.7 ft

7 0
3 years ago
00:00<br> Select all the fractions that are equivalent to 2 /<br> 5<br> Use the area models to help.
AleksAgata [21]

Answer:

this doesnt make sense but the answer is

rcpl 2/5 = 5/2 = 2 1/2

Step-by-step explanation:

2 1/2

8 0
2 years ago
Read 2 more answers
Find the value of z.
Leokris [45]

The exterior angle at the intersection of the tangent and secant has a measure that is half the difference between the intercepted arcs.

... ((10x+20) -80)/2 = 2x+15

... 5x -30 = 2x +15

... 3x = 45

... x = 15

So, the unknown arc to the right has measure

.. 10x + 20 = 10·15 +20 = 170

And the arcs of the circle total 360°.

... 80 + z + 170 = 360

... z = 360 - 250 = 110 . . . subtract 250 from both sides

The appropriate choice for the value of z is

... B. 110

3 0
3 years ago
Y= 2x +2
Airida [17]

Answer:

The system has one solution, at a single point of intersection.

Step-by-step explanation:

I'm going to assume that g and y are the same thing here, on a normal xy-coordinate plane. If there is actually a third dimension, 'g', then I am probably wrong, and I apologize.

For a system of 2 linear equations, a 'solution' is a point of intersection for the two lines.

If the two lines are parallel, they will have no intersection. These two equations are in the form y = mx + b, where m is the slope. <u>If their slopes are the same, then the lines are parallel.</u> The first equation has a slope of 2. The second equation has a slope of 6. 2 ≠ 6, obviously. They are are <u>not </u>parallel, so there is <u>at least one</u> solution (intersection)

If two equations are 'equivalent', then they represent the same exact line and you cannot find a unique solution to the system because there is no single point where they intersect. They intersect at <u>all </u>points, so there are an infinite number of solutions. Two equations in the same format (like point-slope) will be equivalent if you see that one is just a multiple of the other. That is not the case here. They are not equivalent, so there are not an infinite number of solutions.

For the intersection of two lines in a plane, that intersection is no point, 1 point, or infinite points.

We have ruled out no point and we have ruled out infinite points.

There must be a solution of one point where the two lines intersect.

That would be consistent with answers B and E as shown in your Brainly question.

4 0
2 years ago
Read 2 more answers
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