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3 years ago

HELP! will give brainliest if given right answers

Mathematics

2 answers:

disa [49]3 years ago

7 0

7. tails, odd, 4

P(tails) = 1/2

P(odd) = 3/6 = 1/2

P(4) = 1/6

P(tails then odd then 4) = (1/2)×(1/2)×(1/6) = 1/24 ≈ 0.041666

Answer: 1/24, 4.2%

8. tails, 6 or 1, 3

P(6 or 1) = 2/6 = 1/3

P(3) = 1/6

P( tails, 6 or 1, 3) = (1/2)(1/3)(1/6) = 1/36 ≈ 0.027777

Answer: 1/36, 2.8%

9. heads, not 2, even

P(heads) = 1/2

P(not 2) = 5/6

P(even) = 1/2

P(heads, not 2, even) = (1/2)(5/6)(1/2) = 5/24 ≈ 0.208333

Answer: 5/24, 20.8%

mart [117]3 years ago

4 0

Answer:

7. 1/24 = 4.2%

8. 1/36 = 2.8%

9. 1/6 = 16.67%

<em>All percentages are rounded</em>

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Answer:

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Let the radius of the snare drum = r

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3 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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3 years ago