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HACTEHA [7]
3 years ago
10

Which number(s) below belong to the solution set of the equation? Check all that apply

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

salut

X+6=45

X=45-6

X=39


Step-by-step explanation:


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Two figures are shown. EFJL is dialation of ABIK AB has a length of 12 and EF has a length of 3
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The scale factor of dilation from AB to EF is 0.25

<h3>How to determine the scale factor of dilation?</h3>

The given parameters are:

  • EFJL is dilation of ABIK
  • AB has a length of 12
  • EF has a length of 3

From the above parameters, side lengths AB and EF are corresponding sides

This means that:

The scale factor of dilation (k) is

k = AB/EF

So, we have

k = 3/12

Evaluate

k = 0.25

Hence, the scale factor of dilation from AB to EF is 0.25

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Step-by-step explanation:

V = 4/3 × 22/7 × 3³

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3 years ago
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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

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3 years ago
A large room has a temperature of 70 degrees Fahrenheit. When a cup of tea is brought into the room, the tea has a temperature o
masya89 [10]

Answer:

91.3

Step-by-step explanation:

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3 years ago
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The question is just a black box. I would like to help you if you could attach a pic of the problem
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