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3 years ago

Which number(s) below belong to the solution set of the equation? Check all that apply

Mathematics

1 answer:

lys-0071 [83]3 years ago

3 0

Answer:

salut

X+6=45

X=45-6

X=39

Step-by-step explanation:

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The formula for the volume of a sphere is v= 4/3 3.14rWhat is the formula solved for r?

prohojiy [21]

Answer:

$r = \frac{3}{4\pi}V$

Step-by-step explanation:

First, the formula for the volume of a sphere is:

$V = \frac{4}{3}\pi r^3$

$\frac{3}{4}V = \pi r^3$

$\frac{3}{4}V\frac{1}{\pi} = r^3$

$r^3 = \frac{3}{4\pi}V$

$r = \sqrt[\leftroot{-2}\uproot{2}3]{\frac{3}{4\pi}V}$

If there is any steps you are unsure of, feel free to ask in the comments.

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3 years ago

Anna pays $120 per month for plano lessons. Estimate how much Anna pays

Ivanshal [37]

Answer:

1440

Step-by-step explanation:

1440 because u have multiply 120x12 because there r 12 months

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3 years ago

Right Answer to theese three questions please???

Scilla [17]

I hope this helps you

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2 years ago

2HR 37MIN - 1HR 15 MIN

dlinn [17]

Answer:

Step-by-step explanation:

2hours and 37min is not the equivilent to 1hour and 15min

6 0

2 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago