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KonstantinChe [14]
3 years ago
9

How many solutions does the graphed system of equations have:

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

since the lines don't intersect there is no solution.


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Mei and Alberto are selling cookie dough. Mei sold 11 packages of chocolate chip and 12 packages of gingerbread for a total of $
ycow [4]

Answer:

The price of a package of chocolate chip is $13.25

The price of a package of gingerbread is $17.18

Step-by-step explanation:

11x + 12y = 352

10x +8y = 270

Let "x" be the price of a package of chocolate chip.

Let "y" be the price of a package of gingerbread.

11x + 12y = 352(Multiply the 1st row by 10)

10x +8y = 270 (Multiply the 2nd row by 11)

-------------------

110x + 120y = 3520

110x +88y = 2970

--------------------------

        3y = 550

y =550/3

y = 17.1875

The price of a package of gingerbread "y" is $17.18

Let's pick the first equation "110x + 120y = 3520"

110x + 120y = 3520

110x+ 120(17.1875)= 3520

110x+2062.5=3520

110x=3520−2062.5

110x=1457.5

x= 1457.5/110

x=13.25

The price of a package of chocolate chip is $13.25

6 0
2 years ago
What would the inter-rater reliability be for a 50-item measure in which the number of agreements between Rater 1 and Rater 2 wa
nlexa [21]
What would the inter-rater reliability be for a 50-item measure in which the number of agreements between Rater 1 and Rater 2 was 45?
C) 0.90
7 0
3 years ago
A box contains four equal sized cards labeled 1, 3,5, and 7. Tim will select one card from the bow. What is the probability that
Zielflug [23.3K]

Answer: The probability is zero.

Step-by-step explanation:

The labels on the 4 cards are 1, 3, 5 and 7. Because the cards are equal, the probability of dragging at random each one of them is equal to 1/4 = 0.25.

Now, the probability that Tim selects a card labeled with a 4 is equal to the number of cards labeled with a 4, divided the total number of cards.

We do not have cards labeled with a 4, so the probability is:

p = 0/4 = 0

because we do not have any card labeled with a 4, the probability of selecting one at random is equal to zero.

8 0
3 years ago
What’s the difference quotient simplified
mihalych1998 [28]

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

7 0
3 years ago
Solve the equation -15=a/5 <br> A=-3<br> A=-20<br> A=-10<br> A=-75
agasfer [191]

To solve any equation, you do whatever you need to do 
to wind up with the unknown quantity all alone on one side.
BUT ... whatever you do to one side of the equation, you must
also do to the other side.

Here, we have the
he original equation:           -15  =  a/5

Multiply each side by 5 :     -75  =  a

and bada-bing, THERE's the solution !
4 0
3 years ago
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