we conclude that for 500 miles, both plans will have the same cost.
<h3>
For how many miles both plans have the same cost?</h3>
Plan A charges a fixed amount of $75, plus $0.10 per mile, so if you drive x miles, the cost equation is:
A(x) = $75 + $0.10*x
For plan B we will have the similar equation:
B(x) = $100 + $0.05*x
The cost is the same in both plans when:
A(x) = B(x)
So we need to solve the linear equation:
$75 + $0.10*x = $100 + $0.05*x
$0.10*x - $0.05*x = $100 - $75
$0.05*x = $25
x = $25/$0.05 = 500
So we conclude that for 500 miles, both plans will have the same cost.
If you want to learn more about linear equations:
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The acceleration if the object when force is 100N is 10 meters per seconds squared
<h3>How to find the acceleration of the object</h3>
Given the direct variation relationship
force , f α acceleration, a
f = ka
k = constant of variation
solving for k
90 = k * 9
k = 90/9
k = 10
when force is 100N
100 = 10 * a
a = 100 / 10
a = 10
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We are told that statement q is this:
Jose is not winning the race.
Now we have the statement, "Jose is winning the race." In logic, when we put two "not"s in it, they negate each other.
q: Jose is not winning the race.
~q: q: Jose is not not winning the race.
~q: Jose is winning the race.
Thus, ~q - choice C - represents that statement.