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Amanda [17]
3 years ago
6

What is the answer to both of these questions? Please help

Mathematics
2 answers:
Afina-wow [57]3 years ago
7 0

Answer:

28) 120 x 20y

30) 3w x 36

Step-by-step explanation:

28) 20 x (6 x y)

20 x 6 = 120

y x 20 = 20 y

120 x 20y

30) (w x 12) x 3

3 x w = 3w

12 x 3 = 36

3w x 36

oee [108]3 years ago
5 0

Answer:

120 x 20y               3w x 36

Step-by-step explanation:

Distributive Property

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A miner descended 1200 feet into a mine. While in the mine, he then rose 900 feet and then descended 350 feet. What was the mine
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We can just add all these numbers together because they are just addition and subtraction.

We assume the miner starts at 0 (the surface).

0 - 1200 (down) + 900 (up) - 350 (down) = -650 (C)
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Evaluate the expression 5m – 6 for m = 7. 29 41 5 51
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It’s 29 because if you substitute the m by 5 it would be 5*7 so that’s 35 and then 35-6=29
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What is an equation in point-slope form of the line that passes through (1, −6) and (4, 6)
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Answer:

Step-by-step explanation:

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Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are in
VladimirAG [237]

Answer:

The options are endless.

You do have the following requirements to the letters asked about:

c=b  (neither of these can be 0)

d=a

So here is one example:

Choose c=b=4 and d=a=9.

The functions will be:

f(x)=\frac{x+9}{4} and

g(x)=4x-9

Step-by-step explanation:

I'm going to assume my comment above.

In order for f and g to be inverse f(g(x)) has to give you x and g(f(x)) also has to give you x.

f(g(x))

f(cx-d)

\frac{(cx-d)+a}{b}

\frac{cx-d+a}{b}

\frac{cx+(-d+a)}{b}

\frac{cx}{b}+\frac{-d+a}{b}

We want this to equal x.

This means we need the following to happen:

\frac{c}{b}=1 \text{ and } \frac{-d+a}{b}=0

The first one happens when c=b assuming b isn't 0 since you can't divide by 0.

The second one happens when the top is 0 because that is the only way a fraction will output you 0 is if the numerator is 0.

So we d=a as well.

So this is what we need for f and g so that they are inverse:

f(x)=\frac{x+d}{c} since d=a and c=b

g(x)=cx-d

Let's try to see if we get x when doing both f(g(x)) and g(f(x)).

f(g(x))

f(cx-d)

\frac{(cx-d)+d}{c}

\frac{cx-d+d}{c}

\frac{cx}{c}

x

We have confirmation that f(g(x))=x.

g(f(x))

g(\frac{x+d}{c})

c(\frac{x+d}{c})-d

x+d-d

x

So f(x)=\frac{x+d}{c} and g(x)=cx-d are inverses for all choices c and d except when c is 0 since you are not allowed to divide by 0.

Your question says to insert numbers for c (=b) and d (=a).

So an example:

Let b=c=4 and d=a=9.

Let's try it:

These will be our functions with those choices for the constant variables:

f(x)=\frac{x+9}{4} and g(x)=4x-9

f(g(x))

f(4x-9)

\frac{(4x-9)+9}{4}

\frac{4x}{4}

x

We have f(g(x))=x.  Check mark, there.

g(f(x))

g(\frac{x+9}{4})

4(\frac{x+9}{4})-9

x+9-9

x

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3 years ago
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