<u>Given</u>:
Given that HIJ is a right triangle.
The measure of ∠J is 90°, JI = 5, IH = 13, and HJ = 12.
We need to determine the value of sine of ∠H
<u>Value of sine ∠H:</u>
The value of sine ∠H can be determined by using the trigonometric ratios.
Thus, we have;

Substituting the values, we get;

Dividing, we get;

Taking
on both sides, we have;


Rounding off to the nearest hundredth, we get;

Thus, the measure of ∠H is 22.62°
Answer:
y= -16
Step-by-step explanation:
Y= -3x - 1
Let x = 5
y = -3(5) -1
y = -15-1
y = -16
Answer:
(x)=3x^2−12x+16
Answer- =3x2−12x+16
Step-by-step explanation:
Hope this helps :)
Answer:
option B is true.
Step-by-step explanation:
We are given that two functions
f(x)=
and g(x)=sin x and a line x =
We have to find the area of the region bounded in the first quadrant by x=
and two functions
We know that the area bounded by two functions
=Integration of region(Upper curve- lower curve)
Therefore, function of sec square x is upper curve and function of sin x is lower function
Therefore, limit of x changing from 0 to 
Hence, the area of the region bounded in the first quadrant and two functions is given by

Therefore, option B is true.