Answer: First you have to take 20% and make it into a fraction 1/5.
Then you multiply 46.5 and multiply it by 1/5 and get 9.3
Add $46.50 and $9.30 and get $55.80
Step-by-step explanation: Hope this helps!! <3
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
Answer:
LIMIT
The policy will pay for up to
$100,000 of damage to
another person's property.
The policy will pay only
$100 per incident for a
tow truck
DEDUCTIBLE
The policyholder must pay
the first $1,000 of repair
expenses before insurance
will pay for anything,
PREMIUM
The policy offers coverage
for a cost of $178 per month
The policyholder must
pay $500 semiannually
to the insurance provider
Step-by-step explanation:
LIMIT is the maximum amount an insurer will pay toward a covered claim
DEDUCTIBLE is the amount paid out of pocket toward a covered claim
PREMIUM is the amount paid regularly to keep the policy in force.
Answer:
"23,520"
Step-by-step explanation:
one trip: 14 passengers
one day: 3 trips
passengers: 80
80x14= 1,120
1,120x3= 3,360
3,360x7= 23,520
The answer is 114 just divide 228 by 2
