We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function.
Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!
100 is 101 to the nearest ten
The correct answer is C) 900
To begin with, you need to divide the number of days in a year with the number of dogs. When you do this, you multiply it by 50 to get the final answer. In this case, it would be 365 / 20 which when multiplied by 50 gives the number of C) 900 since it's "about" 20 days.
Answer:
16t + 10
Explanation:
Step 1 - Add like terms
-16t + 32t + 10
16t + 10
98 isnt a prime, which means that it is a composite number
