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3 years ago

A club puts its members into 5 groups for an activity. After 7 students have to leave early,

Mathematics

2 answers:

Vlad [161]3 years ago

6 0

Answer:

I think that there were 12 students in each group fam.

Step-by-step explanation:

LuckyWell [14K]3 years ago

5 0

Answer:

i believe it is 12

Step-by-step explanation:

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15% of the content of a 454 g can of dog food is protein. How many grams of protein are in the can?

mote1985 [20]

Answer:

521.1

Step-by-step explanation:

8 0

3 years ago

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What’s the surface area of the prism in square inches? A.300 B.360 C.390 D.460 helpppppp

butalik [34]

Answer:

2) 360 square inches

Step-by-step explanation:

First of all we have to verify that the base triangle is a right triangle

For this we use Pythagoras

h² = l1² + l2²

13² = 12² + 5²

169 = 144 + 25

169 = 169

Equality is fulfilled by what is a right triangle

Now we need to calculate the area of the triangle

a = (12 in * 5 in) / 2

a = 60in² / 2

a = 30in²

Now we have to calculate the 3 areas of the rectangles

a1 = 10in * 13 in

a1 = 130in²

a2 = 10 in * 12 in

a2 = 120in²

a3 = 10 in * 5 in

a3 = 50in²

Now we must add all the calculated areas and the triangle 2 times

a1 + a2 + a3 + 2a =

130in² + 120in² + 50in² + 2 * 30in²

360in²

The surface area of the prism is 360in²

5 0

2 years ago

Read 2 more answers

Please help me i beg of u due today

Zepler [3.9K]

Answer:

110

Step-by-step explanation:

80 + 30

= 110

7 0

3 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

A dealer bought an article for $7 sold it for $8 bought it back for $9 and then sold it for $10 how much profit did he make

Anit [1.1K]

To the total amount of money that a dealer spent is $7 + $9 or %16. His revenue from selling the same articles is $8 + $10 which is equal to $18. The profit is the difference between the total revenue and total cost.
profit = $18 - $16 = $2
Thus, the dealer has a profit of $2.

5 0

2 years ago