PLEASE HELP I NEED TO PASS.Put the following equation into function notation select all answers that are possible

Mathematics

1 answer:

Art [367]3 years ago

8 0

Answer:N I G G E R WAS VERY BAD TO DO BEACSUE YOUR NOT VERY NICE BECASUE NOBODY LIKES YOU

You might be interested in

Need help fast Thank

ollegr [7]

What you need help with

3 0

3 years ago

The pressure at sea level is 11 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of

Taya2010 [7]

Answer:

p(x) = 0.1x + 1

Step-by-step explanation:

Pressure at sea level = 1 atmosphere

Depth dove by Sydney = 23 meters

Pressure at a depth of 23 meters = 3.3 atmospheres

So,

Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney

where k is the diving rate constant

=> 3.3 = 1 + k(23)

=> 3.3 = 23k + 1

Subtracting 1 from both the sides, we get

3.3 - 1 = 23k + 1 -1

Cancelling out the +1 and -1 from the right side, we get

2.3 = 23k

=> 23k = 2.3

Dividing both sides by 23, we get

$\frac{23k}{23} = \frac{2.3}{23}$

Cancelling out the 23's from the top and bottom of the left side, we have

k = 0.1

Plugging in the value of k in the equation, we get

Pressure at a particular depth = Pressure at sea level + k * Depth dove by Sydney

p(x) = 1 + k(x) [where p(x) is the pressure at a depth x]

=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

5 0

3 years ago

4/9 times what equals 1?

ArbitrLikvidat [17]

4/9 *9/4 =1
Use the reciprocal to find your answer :)
Cheers :3

8 0

3 years ago

Victor stands 20 meters from a building that is 45 meters tall. He looks up at the roof edge of the building. What is the measur

Gwar [14]

We know that the height of the building is 45m, and the distance between the building and victor is 20m. Since the problem does not state the height of Victor, we can assume that horizontal line of sight of Victor coincides with the base of the building. This gives us a right triangle with angle x and sides 45m and 20m, as you can see in the diagram.

Now, to find the value of the angle x, we will need a trigonometric function that relates the opposite side of our angle x with the adjacent side of it; that trigonometric function is tangent. Remember that $tangent (\alpha) = \frac{oppositeside}{adjacentside}$

We know for our diagram that the opposite side of Victor's angle of inclination, x, is the height of the building (45m), and the adjacent side of it is the distance between Victor and the building (20m). Now we can replace the values in our tangent equation to get:

$tan(x)= \frac{45}{20}$