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Flauer [41]
3 years ago
14

What point would you have when (-7, 3) is reflected over the line y=x?

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
7 0
I believe it’s C.
The line y=x looks like a even, diagonal line going through (0, 0) on a graph. If you have (-7,3) , your in the first quadrant (in the upper left square of the graph). If you reflect it diagonally, the digits themselves would remain that same, but the value would flip (if it’s positive, it’ll become negative, if it’s negative, it’ll become positive). So if we do that with (-7, 3), it becomes (7, -3).
Solution: (7, -3)
Mekhanik [1.2K]3 years ago
4 0

Answer:

I believe its A.

Step-by-step explanation:

It usually the same numbers but backwards sometimes it just a positive or a negative different.

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A. It is not possible to determine if the triangles are congruent
kirill [66]

Answer:

C. ∆ABD ≅ ∆CBD by the SSS Postulate

Step-by-step explanation:

We can prove that ∆ABD and ∆CBD congruent by the SSS Postulate.

The SSS postulate states that of three sides in one triangle are congruent to three corresponding sides in another, therefore, the two triangles are congruent.

From the diagram shown,

AB ≅ CB,

AD ≅ CD

BD = BD

We have three sides in ∆ABD that are congruent to three corresponding sides in ∆CBD.

Therefore, ∆ABD ≅ ∆CBD by the SSS Postulate

4 0
3 years ago
8/10
taurus [48]

Answer:

220

Step-by-step explanation:

(63/1.4)+10

=45+10

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6 0
2 years ago
(x+5)(x-5) Multiplying special case polynomials
azamat

Answer:

x^2 - 25 ✔

Step-by-step explanation:

(x+5)(x-5)

x(x-5) +5(x-5)

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x^2 - 25

7 0
3 years ago
What is the answer to this problem? <br><br> 2 1/3 + 3 1/3 =?
Naily [24]

Answer:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Exact Form:

173

Decimal Form:

5.¯6

Mixed Number Form:

523

Step-by-step explanation:

3 0
2 years ago
Plz help<br> and explain
vovikov84 [41]
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.

The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

Therefore
Area of band
=(x+10)^2-x^2    [recall (a+b)^2=a^2+2ab+b^2
=x^2+20x+100-x^2
=20x+100   or 20(x+5)  if you wish.

8 0
3 years ago
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