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3 years ago

How much larger is 0.30 than 0.3

Mathematics

1 answer:

Xelga [282]3 years ago

4 0

They are both equal because in decimals you can add thousands of zeros and it's still equal.

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

Simplify:<br><br> {(-8)^-4 ÷ 2^-8}^2

Aleksandr-060686 [28]

Answer:

ok so first we have to do whats in the brackets then we have to do to exponits so first

(-0.00024414062divided by 0.00390625)^2

-0.06249999872^2

-0.00390624984

Hope This Helps!!!

8 0

2 years ago

Read 2 more answers

What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22

sdas [7]

<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120

Median = 90
Lower Median = 73
Upper Median = 101

IQR = 101 - 73
IQR = 28</span>

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=Factor%3A%20x%5E2-9" id="TexFormula1" title="Factor: x^2-9" alt="Factor: x^2-9" align="absmidd

Bezzdna [24]

Answer:

x²-9=x²-3²=(x+3)(x-3)

Step-by-step explanation:

use formula

a²-b²=(a+b)(a-b)

7 0

3 years ago

Miles is playing catch with his friend. He throws the baseball from point A to point B

MAXImum [283]

Answer:

1234567890

Step-by-step explanation:

1234567890

8 0

3 years ago