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3 years ago

-√5 is a real number

1 answer:

4 0

<h2>Answer:</h2><h2>Yes please it is a number but the fact is it a negative integer meaning it has no prime number </h2>

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What us the range of the data below?

MArishka [77]

The range of the data is 12

3 0

3 years ago

Fatima has 50 donuts to sell. Each donut is covered with one topping. 5 are covered with peanuts 15 are covered with chocolate c

vagabundo [1.1K]

Answer:

FATIMA (LOLOLOLOLOLOLOLOLOLOL)

Anyways the correct answer is 10 donuts that are covered with sprinkles

Step-by-step explanation:

5+15+20=40

50-40 = 10

4 0

3 years ago

The width of a rectangle measures (7d + 8f) centimeters, and its

Andre45 [30]

The expression which represents the perimeter, in centimeters, of the rectangle is; (18d +10f) centimetres.

<h3>Perimeter of a rectangle</h3>

Since the perimeter of a rectangle is given by the formula;

Perimeter, P = 2l + 2w.

In essence, Perimeter, P = 2(2d – 3f) + 2(7d + 8f)

P = 4d -6f + 14d +16f

P = 18d +10f.

Ultimately, the perimeter of the rectangle is; (18d +10f) centimetres.

Read more on perimeter of a rectangle;

brainly.com/question/17297081

4 0

3 years ago

An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

3 years ago

Select the four relations that represent a function.

Anton [14]

The first, third, fifth and sixth one are all functions.

8 0

3 years ago

-√5 is a real number​

-√5 is a real number