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3 years ago

Wich step can be done to both sides of the equation to determine the value of x?

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

Add 9.6 to both sides and then divide both sides by 3.2

Step-by-step explanation:

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The regression equation y = -0.414x + 106.55 approximates the percent of people in an

murzikaleks [220]

The correct option will be: A. 67%

Explanation

Given equation is: $y = -0.414x + 106.55$ , where $x$ is the length of the film in minutes and $y$ is the percentage of people finish watching the film.

Here, the length of the documentary is given as 95 minutes. So, we will plug $x=95$ into the above equation and get....

$y=-0.414(95)+106.55\\ \\ y=-39.33+106.55\\ \\ y=67.22 \approx 67$

(Rounded to the nearest percent)

So, the percentage of people in an audience who will finish watching a documentary that is 95 minutes long will be 67%

4 0

3 years ago

Write as a fraction. Reduce fractions. Use the "/" key for the fraction bar. 37.5%

Tems11 [23]

That would be 3/8
Because 1/8 = 12.5 %

3 0

3 years ago

I need help for these questions please

Marat540 [252]

A) 90-55=35 since a right angle is 90 total\
b)ii

7 0

2 years ago

A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s

mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, $\theta=25$ °

Initial speed is, $u=15\ m/s$

Time of flight is, $t=3.0\ s$

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

$u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s$

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = $-h$ (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, $g=-9.8\ m/s^2$

Now, using the following equation of motion;

$-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m$

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, $v_y=0\ m/s$

Now, using the following equation of motion, we have:

$v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m$

Therefore, the maximum height of the brick is 2.05 m.

5 0

3 years ago

What is 40 percent of 90 percent

Brums [2.3K]

Answer:0.36

or 36

Step-by-step explan: used calculator

5 0

2 years ago