Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:

In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So

Applying implicit differentiation.
We have two variables, A and r, so:



The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Answer:
the supplementary angle to 313 would be 49.
Step-by-step explanation:
the supplement of an angle is when tow angles add up to equal 180 degrees. therefore, if you subtract 131 from 180, you would get the answer of 49 degrees.
Answer:
A, 120.
Step-by-step explanation:
x-15+75=180
x+60=180
x=120.
simplify the expression, <em> -4/7 + 2/7 x - 14 x + 4 / 7</em>
Answer : <em>-96x/7</em>
Answer: (-1,-6) because you are just changing the y-axis when reflecting over the x-axis so the x-value doesn't change.