3 years ago

What is an equation of the line in point slope form that passes through the given point and has the given slope?

Mathematics

1 answer:

NemiM [27]3 years ago

3 0

It is the fourth option, y+8=3(x-8)

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Please help me to do this sinx+cosx-sin(x-30)+cos(x-30)=√6cos(x-15)

miv72 [106K]

The correct answer is 4x to the third power.

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3 years ago

Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3).

jonny [76]

Answer:

$y=\frac{3}{4}x^2$

Step-by-step explanation:

Hi there!

Because we're given the vertex of the parabola, we can determine its equation in vertex form:

$y=a(x-h)^2+k$ where the vertex is $(h,k)$

Plug in the vertex (0,0)

$y=a(x-0)^2+0\\y=a(x)^2\\y=a(x-0)^2+0\\y=ax^2$

Now, we must solve for a. Plug in the given point (-2,3) and solve for a:

$3=a(-2)^2\\3=4a\\\frac{3}{4} =a$

Therefore, the value of a is $\frac{3}{4}$ . Plug this back into $y=ax^2$ :

$y=\frac{3}{4}x^2$

I hope this helps!

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3 years ago

Use the diagram to complete this proportion.

Stolb23 [73]

Answer:

Step-by-step explanation:

This is not 100% but I think this is the answer

8 0

3 years ago

If the triangles are similar, find the scale factor from triangle DEF to triangle ABC.

Tatiana [17]

Answer:

3/2

Step-by-step explanation:

divide 33 by 22, you get 1.5

3/2 is 1.5 so ya

5 0

3 years ago

Read 2 more answers

What is the exact value of arccos(−2√2) ?

Strike441 [17]

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is $-1\le \cos x\le 1$

Therefore $arc \cos (-2\sqrt{2})$ is not defined.

Assuming your question is rather $arc \cos (-\frac{\sqrt{2}}{2})$

Then $arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})$ in the second quadrant.

$arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}$

$arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}$

4 0

3 years ago