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2 years ago

10

‼️ What is the height of a right triangle with an angle that measures 60 degrees and a base of 14 adjacent to the 60 degree angl

e???

1 answer:

puteri [66]2 years ago

7 0

You'd use tangent for this.

opposite / adjacent

tan 60* = x/14

multiply both sides by 14

tan 60* = 1.73

tan 60* (1.73 x 14) = x

24.22 = x

Your answer should be 24.22

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Identify each pair of angles as corresponding, alternate interior, alternate exterior, or consecutive interior.

zhuklara [117]

Answer:

1. The answer for this question is corresponding angles.

2. The answer for this question is alternate interior

6 0

3 years ago

a ball is shot straight upward. with it's height, in feet, after t seconds given by the function f(t)=-16t^2+192t. Find the aver

jekas [21]

ANSWER

$80 {ms}^{ - 1}$

EXPLANATION

The average velocity of the ball is the rateof displacement over the total time.

The height of the ball, in feet, after t seconds is given by the function:

$f(t)=-16t^2+192t$

At time t=1, the height of the ball is

$f(1)=-16(1)^2+192(1)$

$f(1)=-16+192 = 176ft$

At time t=6, the height of the ball is

$f(6)=-16(6)^2+192(6)$

$f(6)=-16(36)+192(6)$

$f(6)=-576+1152 = 576$

The average velocity

$= \frac{f(6) - f(1)}{6 - 1}$

$= \frac{576- 176}{6 - 1}$

$= \frac{400}{5}$

$= 80 {ms}^{ - 1}$

7 0

3 years ago

Please help me! I really need someone to explain how to find the perimeter also. Thank you in advance!

andrezito [222]

You add all the sides together and divide by the number of side so in your case it would be 6 sides and you should get your perimeter i think thats how you do it i could be wrong

5 0

3 years ago

Read 2 more answers

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago

X+3<8 and 3(x+4)-11<10

kondaur [170]

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

4 0

3 years ago