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3 years ago

10. A 266-hp output is required for an engine. If there is a 5% loss of power, what amount of input

Mathematics

1 answer:

marta [7]3 years ago

7 0

Answer:

Amount of input horsepower needed is 279.3 hp.

Step-by-step explanation:

if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.

Now to calculate 5% of 266 hp, we can write

266 × $\frac{5}{100}$ = 13.3 hp

Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.

So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp

To know more about horsepower and percentage problem:

brainly.com/question/24585630

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Match the following items.

max2010maxim [7]

Answer:

1. ∠ABD = 20°.

2. Arc AB = 140°.

3. Arc AD = 40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

$\angle DAB=90^{\circ}$

Using angle sum of property in triangle ADB we get,

$\angle ADB+\angle DAB+\angle ABD=180^{\circ}$

$70^{\circ}+90^{\circ}+\angle ABD=180^{\circ}$

$\angle ABD=20^{\circ}$ .

Draw a line segment AO.

In triangle AOD, AO=OD, so

$\angle ODB=\angle OAD=70^{\circ}$

Using angle sum property in triangle AOD,

$\angle AOD+\angle ODA+\angle OAD=180^{\circ}$

$\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}$

$\angle AOD=40^{\circ}$

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

$\angle AOD+\angle AOB=180^{\circ}$

$40^{\circ}+\angle AOB=180^{\circ}$

$\angle AOB=140^{\circ}$

Therefore length of arc AB is 140°.

3 0

3 years ago

Which circle has a central angle that measures 40°?

Varvara68 [4.7K]

Answer:

Option B.

Step-by-step explanation:

We need to find the circle that has a central angle that measures 40°.

In all options, the center of circle is U. It means central angle must be on center, i.e., U.

In option A,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.

In option B,the angle VUZ is at point U which is the center. So, angle VUZ is a central angle with measure 40°.

In option C,the angle XZV is at point Z which is not the center. So, angle XZV is not a central angle.

In option D,the angle VXZ is at point X which is not the center. So, angle VXZ is not a central angle.

Therefore, the correct option is B.

8 0

3 years ago

Math IIIB Performance Task: Piecewise-Defined Functions

meriva

9514 1404 393

Explanation:

a) see the attachment for a graph (red curve)

b) The piecewise defined function can be ...

$\displaystyle C(x)=\begin{cases}0&0\le x\le 1\\5&1$

c) The new cost function is ...

$\displaystyle C(x)=\begin{cases}10&0\le x\le5\\x+5&5$

The charge is a flat $10 for any period up to 5 hours, then $1 per additional hour after that, prorated for partial hours. There is apparently no upper limit on parking time as there was with the original function. (The graph shown goes beyond 15 hours; the domain of the original C(x) is 0 to 12 hours.) For reference, the new cost structure is shown in blue in the attachment.

_____

<em>Additional comment</em>

Under the new structure, costs are significantly higher for short-term parking, and lower once the term exceeds 6 hours.