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3 years ago

Describe the position of all the points on the number line that are

Mathematics

1 answer:

zimovet [89]3 years ago

3 0

A. all number greater than a will be to the RIGHT of a

b. all numbers less than a will be to the LEFT of a

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What’s the correct name for that line?

eimsori [14]

GM, because when naming a line, you go from left to right just like how we read.

8 0

4 years ago

what is 12/3 as an improper fraction? a. 2/3 b. 5/3 c. 8/3 d. 6/3 user: what is 20 × 6? a. 100 b. 40 c. 12 d. 120

Sedbober [7]

$1\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\boxed{\dfrac{5}{3}}\to\fbox{b.}\\\\20\times6=6\cdot(2\cdot10)=6\cdot2\cdot10=12\cdot10=\boxed{120}\to\fbox{d.}$

7 0

3 years ago

Simplify X 1/2 times X 2/3

vovikov84 [41]

Answer:

3/6x • 4/6x

12/6x

Step-by-step explanation:

you would change both fractions to have the same denominator then simplify if needed

5 0

3 years ago

Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911

nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

$\lambda=\dfrac{1}{2}$

(a) What is the expected number of 911 calls in one hour?

$\lambda=\dfrac{1}{2}\times 60=30$

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

$\lambda=\dfrac{1}{2}\times 5=2.5$

Number of calls = 3

So, P(X=3) is given by

$P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138$

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

$P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820$

Hence, a) 30, b) 0.2138, c) 0.0820

4 0

3 years ago

Please help using law of cosines!

Tamiku [17]

Answer:

∠ A ≈ 48°

Step-by-step explanation:

Using the Cosine rule to find an angle

cosA = $\frac{b^2+c^2-a^2}{2bc}$

with a = 10, b = 13 and c = 11

cosA = $\frac{13^2+11^2-10^2}{2(13)(11)}$

= $\frac{169+121-100}{286}$

= $\frac{190}{286}$ , thus

A = $cos^{-1}$ ( $\frac{190}{286}$ ) ≈ 48° ( to the nearest degree )

6 0

3 years ago