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satela [25.4K]
3 years ago
10

write an equation in slop-intercept form for a line that is perpendicular to the line y= -5x-3 and has a y-intercept of 6.

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

Answer:

The equation of the line would be y = 1/5x + 6

Step-by-step explanation:

First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is -5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.

Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.

y = mx + b

y = 1/5x + 6

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Step-by-step explanation:

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Answer:

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3 years ago
Find the equation of the line with a slope of 3/4 and passes through (4-2)
Ira Lisetskai [31]

Answer:

y = 3/4x - 5

Step-by-step explanation:

An equation of a line can be written in slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept.

Let's plug in what we know.

The slope is 3/4.

y = 3/4x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.

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To find b, multiply the slope and the input of x(4)

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Plug this into your standard equation.

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This is your equation. It has a slope of 3/4, and passes through (4, -2)

Hope this helps!

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