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kozerog [31]
3 years ago
11

Roses produced asexually from cuttings are genetically identical to the parent. Roses grown from sexually produced seeds may loo

k different from either parent.
Which statement is best supported by this information?

Sexually produced plants are a new species.

Sexual reproduction produces more variation in plants.

Asexually produced plants are larger than sexually produced plants.

Asexual reproduction helps plants adapt to different environments.
Mathematics
2 answers:
Ksju [112]3 years ago
7 0

The correct answer would be B. Sexual reproduction does infact create more variation in plants.

Kamila [148]3 years ago
7 0

Answer:

Step-by-step explanation:

During , vegetative propagation a new plant grows from parts of the parent plant.

During , Binary fission a cell divides to produce a new, genetically identical cell.

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So if a shape has 7 sides it will have 7 lines of symmetry.

Its always going to be the same number.

plz mark me as brainliest :)

8 0
3 years ago
Jonathan wants to the new baseball game for his game console. The game costs $45.99. If sales tax is 6%, write an equation to fi
gladu [14]
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7 0
2 years ago
Darren has a wooden board that is Three-fifths of a meter long. He cuts the board into 3 equal parts. How long is each section o
Alik [6]

Answer:

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

Step-by-step explanation:

3/5 divided by 3 is the equation we have to do.

3/5 divided by 3 is also equal to 3/5 times the reciprocal of 3 or 1/3

3/5 * 1/3

3*1 = 3

5*3 = 15

3/15 which can simplify to 1/3. (divide numerator and denominator by 3.)

Each section of the board is 1/3 or 0.334(0.333333333333) of a meter

8 0
2 years ago
Write an expression that is equivalent to 3/5 (3y+15)<br> 3/5y +9, 3/5y+15, 9/5y+9, 9/5y + 15?
NISA [10]
Given the expression

\frac{3}{5} (3y+15)

The expression that is equivalent to the given expression is given by:

\frac{3}{5} (3y+15)= \frac{9}{5} y+ \frac{3}{5} (15)= \frac{9}{5} y+9
6 0
3 years ago
Find the sum and product of the roots. 2x^2 + 6x - 8 = 0
netineya [11]
Suppose you can factorize:

ax^2+bx+c=a(x-r_1)(x-r_2)

Then by expanding the right side, you have

ax^2+bx+c=a(x^2-(r_1+r_2)x+r_1r_2)=ax^2-a(r_1+r_2)x+ar_1r_2

which means in this case, you have to have

\begin{cases}6=-2(r_1+r_2)\\-8=2r_1r_2\end{cases}\implies\begin{cases}r_1+r_2=-3\\r_1r_2=-4\end{cases}
3 0
3 years ago
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