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2 years ago

15

To avoid a storm, a passenger-jet pilot descended 0.57 mile in 0.6 minute. What was the plane's average change of altitude per m

inute?

1 answer:

Elan Coil [88]2 years ago

4 0

Answer:

0.95 miles/minute

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QUICK PLEASE HELP ME!!!!!

11111nata11111 [884]

Answer:

E

Step-by-step explanation:

Hopefully this isn't too late. My work is attached below.

8 0

2 years ago

Which would be used to solve this equation? Check all that apply.

puteri [66]

Answer:

multiplying both-side of the equation by 3

substituting 36 for p to check the solution

Step-by-step explanation:

To solve the equation p/3 = 12, we will follow the steps below;

first multiply 3 to both-side of the equation, that is:

p/3 × 3 = 12 × 3

On the left-hand side of the equation, 3 at the numerator will cancel-out 3 at the denominator, leaving us with just p while on the right-hand side of the equation 12 will be multiplied by 3

p= 36

To check the correctness of the equation, we can substitute p = 36 back into the equation and then check, that is;

p/3 = 12

36/3 = 12

This implies p = 36 is correct

3 0

2 years ago

Kendra bought a pieace of fabric that was 14 feet long .lisa bought a pieace of fabric that was 3 yards long .kendra wanted to c

storchak [24]

3 yards is equivalent to 9 feet, so you do 14 - 9 = 5 feet that she has to cut off.
Hope this helps!

5 0

3 years ago

30/80=e/40 what is the answer?

masya89 [10]

Answer:

15

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

please help :{ brainliest if you can get it right and I need you to prove why your answer is correct, thanksss

beks73 [17]

Answer:

The Value of $a=\frac{15}{4}$ .

Step-by-step explanation:

We have Named the figure please find the attachment for your reference.

Given:

PR = y

QR = a

RS = b

PS = z

PQ = x

QS = 15

∠P = 90°

∠R = 90°

∠Q = 60°

∠S = 30°

We need to find the Value of 'a'.

Solution:

Now we know that:

In Δ PQS

∠P = 90°

∠S = 30°

Now we know that;

$sin\ \theta = \frac{opposite\ side}{Hypotenuse}$

$sin \ S= \frac{PQ}{QS}$

Substituting the given values we get;

$sin\ 30\°=\frac{x}{15}$

Now we know that;

$sin\ 30\° = \frac12$

So we can say that;

$\frac{1}{2}=\frac{x}{15}\\\\x=\frac{15}{2}$

Now In Triangle PQR.

∠R = 90°

∠Q = 60°

So we can say that;

$Cos \theta = \frac{adjacent \ Side}{Hypotenuse}\\$

$Cos\ Q = \frac{QR}{PQ}$

Substituting the given values we get;

$cos 60\°= \frac{a}{x}$

Now we know that;

$cos 60\°= \frac12$

$x=\frac{15}{2}$

So substituting the values we get;

$\frac{1}{2}=\frac{a}{\frac{15}{2}}$

By Using Cross Multiplication we get;

$a= \frac{1}{2}\times\frac{15}{2}\\\\a=\frac{15}{4}$

Hence The Value of $a=\frac{15}{4}$ .

6 0

3 years ago