Distribute the number outside the parenthesis and do the equations in the parenthesis. If there is no sign in between the parenthesis, assume to multiply.
A vertical line is a line that is straight up and down. It doesn't tilt. Think of a flagpole as one of many examples.
I suggest plotting the point (-0.4, 0.3) on the coordinate grid. Draw a vertical line through this point. You'll see that there are other points on this line such as...
(-0.4, 0) and (-0.4, 2) and (-0.4, 5)
and so on...
There are infinitely many points on this line. All of them have the same x coordinate of -0.4 since that's what the original point has. Y can be anything you want.
So the equation of this line is simply x = -0.4 to indicate "force x to be -0.4 and y can be whatever you want"
Is this the entire question or can you supply and image of it?
Step-by-step explanation:
This assembly required more than 40 missions. A partnership between European countries (represented by ESA), the United States (NASA), Japan (JAXA), Canada (CSA) and Russia (Roscosmos), the International Space Station is the world's largest international cooperative programme in science and technology.
Y=2x^2+36x+170 setup equation this way to find the parabola.
Binomial should equal zero. Disregard the constant value of 170 and replace with c. So, 0=2x^2+36x+c is your equation.
Switch your x from right to left side showing 2x^2+36x=0, divide by two and simplify. Setup like this: 2x^2/2 + 36x/2 = 0/2. Becomes, x2 +36x/2=0/2.
Reduce common factors to equation reads x2+18x=0/2. Divide zero by two to get 0 so, it looks like this x^2+18x=0.
Create a trinomial square on the left side of equation, you must find a value equal to the square of half of b, coefficient of x which is (b/2)^2=(9)^2 add this term to each side of the equation to get x^2+18x+(9)^2=0+(9)^2. Simplify.
x^2+18x+81=81. Now, factor the perfect trinomial square into (x+9)^2 into (x+9)^2=81. Move the new constant to the left side equation. Becomes,
2(x+9)^2 - 162=0. Now, add the original constant to the new constant to get
2(x+9)^2 - 162+170=0. You must complete the square in the expression
2x^2+36x+170 for 2(x+9)^2 + 8. Now, reorder the right side of the equation, matching the vertex form of a parabola which is y=2(x+9)^2+8. You must use the vertex form y=a(x-h)^2+k to figure out the values of a, h, and k.
a=2 h=-9 k=8 the vertex of (h, k) is (-9,8).
