Answer:
The % growth rate is 15.8%.
Step-by-step explanation:
Let the function is given by , where f(w) is the number of a specific product produced after w weeks.
Now, given for w = 0, f(0) = 190 = a
So, the function becomes ............. (1)
Now, it is also give that at w = 1, f(1) = 220.
So, from equation (1) we get,
⇒ b = 1.15789.
Now, b = 1 + r
⇒ 1.15789 = 1 + r
⇒ r = 0.15789
Therefore, the % growth rate is 0.15789 × 100% = 15.8% (Approx.)
Answer:
0.91517
Step-by-step explanation:
Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.
Let A - the event passing in SAT with atleast 1500
B - getting award i.e getting atleast 1350
Required probability = P(B/A)
= P(X>1500)/P(X>1350)
X is N (1100, 200)
Corresponding Z score =