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tensa zangetsu [6.8K]
3 years ago
7

What is one and a half added to three and a half?

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0
One and a half = 1.5
Three and a half = 3.5
1.5 + 3.5 = 5.
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Distribute the number outside the parenthesis and do the equations in the parenthesis. If there is no sign in between the parenthesis, assume to multiply. 
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Write an equation of the line that satisfies the given conditions. through (-0.4,0.3) vertical
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A vertical line is a line that is straight up and down. It doesn't tilt. Think of a flagpole as one of many examples.

I suggest plotting the point (-0.4, 0.3) on the coordinate grid. Draw a vertical line through this point. You'll see that there are other points on this line such as...
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There are infinitely many points on this line. All of them have the same x coordinate of -0.4 since that's what the original point has. Y can be anything you want. 

So the equation of this line is simply x = -0.4 to indicate "force x to be -0.4 and y can be whatever you want"
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Who jointly built the International Space Station?
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Step-by-step explanation:

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I neex help converting this from standard form into vertex <br><br> f (x)=2x^2+36x+170
dezoksy [38]
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Binomial should equal zero. Disregard the constant value of 170 and replace with c. So, 0=2x^2+36x+c is your equation.
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Reduce common factors to equation reads x2+18x=0/2. Divide zero by two to get 0 so, it looks like this x^2+18x=0.
Create a trinomial square on the left side of equation, you must find a value equal to the square of half of b, coefficient of x which is (b/2)^2=(9)^2 add this term to each side of the equation to get x^2+18x+(9)^2=0+(9)^2. Simplify.
x^2+18x+81=81.  Now, factor the perfect trinomial square into (x+9)^2 into (x+9)^2=81.  Move the new constant to the left side equation. Becomes, 
2(x+9)^2 - 162=0.  Now, add the original constant to the new constant to get
2(x+9)^2 - 162+170=0.  You must complete the square in the expression
2x^2+36x+170 for 2(x+9)^2 + 8.  Now, reorder the right side of the equation, matching the vertex form of a parabola which is y=2(x+9)^2+8.  You must use the vertex form y=a(x-h)^2+k to figure out the values of a, h, and k.
a=2   h=-9   k=8   the vertex of (h, k) is (-9,8).

 



4 0
3 years ago
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