Yo! This is the answer. Hope it helped
Answer:
y = 2x - 4
Step-by-step explanation:
Rearrange the given equation to slope-intercept form.
x + 2y = 2
2y = -x + 2
y = -1/2x + 1
The slope of the given line is -1/2. The slope of a perpendicular line will be the negative inverse, meaning that the slope will be 2.
-1/2 = 2
Find the equation of the new line with the point-slope form using the new slope and given point.
y - y₁ = m(x - x₁)
y - 6 = 2(x - 5)
y - 6 = 2x - 10
y = 2x - 4
The equation will be y = 2x - 4.
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
