X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Your hand looks nice...
Anyway, 11/4 is the answer
Answer:
c
Step-by-step explanation:
Subtract 100 from both sides to get x by itself.
x = 163
(Another way of writing this is "263 - 100 = " like you would see in elementary school.)
Step-by-step explanation:
3/4x + 5/8 = 4x/1
5/8 = 4x/1 - 3/4x
5/8 = 16x^2 - 3/4x
5/8 = 4x - 3/1
5/8 = 4x - 3
Cross multiply
8(4x - 3) = 5
32x - 24 = 5
32x = 5 + 24
32x = 29
X = 29/32
What are we exactly supposed to solve for here
