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2 answers:
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Answer:
The lateral area is 624 unit²
Step-by-step explanation:
* Lets explain how to solve the problem
- The regular square pyramid has a square base and four congruent
triangles
- The slant height of it = , where
b is the length of its base and h is the perpendicular height
- Its lateral area = , p is the perimeter of the base
and l is the slant height
* Lets solve the problem
∵ The base of the pyramid is a square with side length 24 units
∵ Its perpendicular height is 5 units
∵ The slant height (l) =
∴ l = The slant height of it =
∴ l =
∴ l = 13 units
∵ Perimeter of the square = b × 4
∴ The perimeter of the base (p) = 24 × 4 = 96 units
∵ The lateral area =
∴ The lateral area =
∴ The lateral area = 624 unit²
* The lateral area is 624 unit²
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have
case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1
case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2
"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?
well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.
well, we can check by simply getting the distance from the center to the point (4,-1).