Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
Answer:
y = 1/3x + 5/3
Step-by-step explanation:
An equation contains a slope and y-intercept, in the form y = mx + b. To find the slope or m, you need to plug the coordinates into the slope formula.
y2 - y1/ x2 - 1
3 - 0/ 4 - (-5)
= 3 / 9
= 1/3
Now that we know the slope, we need to plug the values of x and y to find the y-intercept.
y = 1/3x + b
3 = 1/3(4) + b
3 = 4/3 + b
5/3 = b
The equation is y = 1/3x + 5/3
Answer:
(x + 5)(x + 10) = 0
Step-by-step explanation:
When you solve for the equation:
, you get that the answer is
.
<em>Hope this helped!!</em>
Answer:
10
Step-by-step explanation:
2 [32 - (4 - 1)³]
2[32 - (3)³]
2[32 - 27]
2[5]
10