3 years ago

What is the gcf of 12 and 8

Mathematics

2 answers:

Bingel [31]3 years ago

6 0

The GCF is 4 12/2=6/2=3 8/2=4/2=2 2*2=4

Alika [10]3 years ago

5 0

2 x 2 x 3 = 12. So 12 is the GCF

Happy studying ^_^

You might be interested in

Segment AB is shown on the graph. Which shows how to find the x-coordinate of the point that will divide segment AB into a 2:3 r

GrogVix [38]

Answer:

$x=\dfrac{2}{5}\times (2+3)-3$

Step-by-step explanation:

The given ratio is 2:3.

x₁ = -3, x₂ = 2

We need to find the x-coordinate of the point that will divide segment AB into a 2:3 ratio. The formula is as follows :

$x=\dfrac{a}{a+b}(x_2-x_1)+x_1$

Put all the values,

$x=\dfrac{2}{2+3}(2-(-3))+(-3)\\\\=\dfrac{2}{5}\times (2+3)-3$

Hence, the correct option is (d).

5 0

2 years ago

Read 2 more answers

if a system of equations consists of 2 parallel lines, then how many solutions does it have? plz answer ASAP

lyudmila [28]

It has 0 solution there are no meeting points of the two given lines.

6 0

3 years ago

11. A bag contains 250 pieces of candy. There are 125 grape, 25 cherry, 25 lemon, 50 strawberry. What is the probability of draw

Andrews [41]

1/10 is the probability.

You find this by putting 25/250 and simplifying.

5 0

2 years ago

Read 2 more answers

Write an equation for the nth term of the arithmetic sequence 12,14,16,18

Elan Coil [88]

$\bf 12~~,~~\stackrel{12+2}{14}~~,~~\stackrel{14+2}{16}~~,~~\stackrel{16+2}{18}\qquad \qquad \stackrel{\textit{common difference}}{d = 2} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=12\\ d = 2 \end{cases} \\\\\\ a_n=12+(n-1)2\implies a_n=12+2n-2\implies a_n=2n+10$

4 0

3 years ago

Which of the following is not a possible value for a probability?

USPshnik [31]

Probability can never be greater than 1. Therefore 11.05 is not a possible value for a probability.

6 0

2 years ago

Read 2 more answers