First, let's put this in Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
4y - 2x = 24 Add 2x to both sides
4y = 2x + 24 Divide both sides by 4
y = (1/2)x + 6
Now that we're in slope-intercept we can easily find the y and x intercepts/
b = 6, so the y-intercept equals 6. Plug zero in for x to confirm!
Now we plug 0 in for y to find the x intercept:
0 = (1/2)x + 6 Subtract 6 from both sides
-6 = (1/2) x Multiply both sides by 2
-12 = x
The x intercept is -12
In Conlusion:
x-intercept = -12
y- intercept = 6
If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.
![\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}](https://tex.z-dn.net/?f=%5Cimplies%20z%3D%5Csqrt%5B7%5D%7B2%5E7%7D%20e%5E%7Bi%5Cfrac17%5Cleft%28%5Cfrac%5Cpi2%2B2n%5Cpi%5Cright%29%7D)
(where <em>n</em> = 0, 1, 2, …, 6)
9514 1404 393
Answer:
(3) p^3 -3p
Step-by-step explanation:
(a +1/a) = p . . . . . . . given
(a +1/a)^3 = p^3 . . . . . . . . cube both sides
a^3 +3a^2(1/a) +3a(1/a)^2 +(1/a)^3 = p^3 . . . . . . expand
(a^3 +1/a^3) +3(a +1/a) = p^3 . . . . . . . . . . simplify, group
(a^3 +1/a^3) +3p = p^3 . . . . . . . . . . substitute p for a+1/a
(a^3 +1/a^3) = p^3 -3p . . . . . . subtract 3p from both sides
Answer:
54
Step-by-step explanation
You can't find the other sides, it may seem impossible, but you have to look at this problem in a different way. To find the perimeter of any figure you just need to know the top base, bottom base, right side, and left side.
We see that the top base equals to the bottom base as it is a rectilinear figure. You have to treat the side with 8 and side with 5 as one base. So they equal 13. Now do the same for the bottom.
So, 13 + 13 = 26
The right side is equal to the left side as it is a rectilinear figure, so the right side is 4 + 10 = 14. The left side is also 14.
So 14 + 14 = 28
26 + 28 = 54 units
Sorry, if I couldn't explain properly. I tried my best. As it is hard for me to explain in words. If I could draw it out, I could do better.
Answer:
3000
Step-by-step explanation:
There are 5 odd digits, so 5^3 = 125 ways to have 3 odd digits.
Given 3 odd digits, the first digit can be even, but not zero, so there are 4 ways to do that.
The second, third, or fourth digits can be even 5 ways, so there are ...
125(4 +5 +5 +5) = 2375
ways to have 3 odd digits in a 4-digit number.
__
There are 5^4 = 625 ways to have 4 odd digits.
The number of 4-digit numbers with 3 or 4 odd digits is ...
2375 +625 = 3000
