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rosijanka [135]
2 years ago
8

Aahuti bought a mobile for Rs.16000 and solve to Aarati at a profit of 20%.Aarati sold it to Aakriti with 10%loss. find out the

cost price of both Aarati and Aakriti​
Mathematics
1 answer:
AveGali [126]2 years ago
4 0

Answer:

1) 19200- for Aarati 2) 17280- for Aakriti

Step-by-step explanation:

1. 16000/100*20=3200- THE MONEY WHICH ARE THE PROFIT,

2. 16000+3200=19200- THE PRICE for Aarati

3. 100-10=90 PERCENTS - the price for AAkriti contains from the price from Aarati

4. 19200*(90/100)= 17280- the price for Aakriti

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The graph third represents the provided situation first line increases and then constant then again increases and becomes constant.

<h3>What is a line graph?</h3>

A line graph is a graph made up of segments of straight lines that connect the depicted data points.

We have:

Keisha ran to swim practice but needed to stop by her friend Natasha’s house on the way. She stayed at Natasha’s house for 15 minutes, and together they ran the rest of the way to practice, where they stayed for 1 hour.

Based on the information given we can say graph third represents the situation.

First Keisha ran to swim practice so the line first increases and then she  but needed to stop by her friend Natasha’s house on the way. She stayed at Natasha’s house for 15 minutes which means the line should be constant.

Again they both ran so line increases.

Then they both stayed for 1 hour, so the line should be constant.

Thus, the graph third represents the provided situation first line increases and then constant then again increases and becomes constant.

Learn more about the line chart here:

brainly.com/question/23680294

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2 years ago
Please help me! Two quantities are related, as shown in the table:
Fynjy0 [20]
I don't know where you got those answers, but the actual equation that represents those points is: y = -1/2x + 11. None of those listed above are correct.
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3 years ago
¿porque algunos objetos flotan y otros se hunden en el agua​
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Answer:

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8 0
3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


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3 years ago
Jacob and Ashley run an animal shelter that houses only cats and dogs. they have 37 adult animals 21 cats and 16 dogs. A group o
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The probability of that arrangement happening = 1/8^2 = 1/64 = 0.00156
3 0
3 years ago
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