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2 years ago

Find the slope between the following points:

Mathematics

1 answer:

bazaltina [42]2 years ago

7 0

Answer:

1. y = -0.6x + 5.4.

2. The entered points belong to a vertical line. There is no slope.

Equation: x = 6

3. y = 0.16667x + 5.5.

4. The entered points belong to a vertical line. There is no slope.

Equation: x = -8.

Step-by-step explanation:

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Can u help me plz ?

natita [175]

Answer:

82 grams

Step-by-step explanation:

each rubber band weighs 3 grams because when 2 bands were added to 88 grams it went up 6 grams and six divided by 2 equals 3.

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3 years ago

Which of the is not a function

Lina20 [59]

Answer:

Step-by-step explanation:

For a function the value of the variable "x" must correspond to a single value of "y"

Hope this helps

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2 years ago

(–1) + 5 – (–6) – 5 =

Svetlanka [38]

Answer:

Step-by-step explanation:

(-1) + 5 - (-6) - 5 =

4 - (-6) - 5 =

10 - 5 =

6 0

2 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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2 years ago

A person washers c cars and earns a total of d dollars

Paha777 [63]

Answer:

because of his big work that hes doing and because he earns it

Step-by-step explanation:

3 0

2 years ago