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Katyanochek1 [597]
3 years ago
12

Joe has some money is his bank account. He deposits $45. Write an expression that represents the amount of money inJoe's account

.
Mathematics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

x +45

Step-by-step explanation:

It could be the only correct answer seeing as it does not state how much money Joe already has in his bank account

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I need help plz
shusha [124]

The solution for given linear equation systems is (3,-4).

Option: C

<u>Step-by-step explanation:</u>

The given equations are 5x+3y=3 and x+y= -1.

Let us isolate x value from equation 5x+3y=3.

5x = 3-3y.

x=\frac{3-3y}{5}.

Substitute this x value in equation x+y= -1.

\frac{3-3y}{5}+y=-1.

After taking LCM for the denominator,

\frac{3-3y+5y}{5}= -1.

3-3y+5y=-5.

2y=-8.

y=-4.

For x=\frac{3-3y}{5} substitute the y value.

x=\frac{3-3(-4)}{5}.

x=\frac{3+12}{5}.

x=\frac{15}{5}.

x=3.

∴ The solution is (3,-4).

8 0
3 years ago
Which table does NOT represent a function?<br> A) A <br> B) B <br> C) C <br> D) D
atroni [7]

Answer: The answer is D

Step-by-step explanation: I just did the question.

7 0
4 years ago
Is x+y=10 a direct variation?
arlik [135]
✡ Answer: True (yes) <span>✡

- -Why?

Because we can determine its a direct variation just based upon the x and y.

</span>✡Hope this helps<span>✡</span>
5 0
3 years ago
Read 2 more answers
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
Solve the system of equation below x+y+z=2 x-y+5z=6
mamaluj [8]
X + y + z = 2
x - y + 5z = 6

cancelando +y com -y:

x + z = 2*(-5)
x + 5z = 6

-5x -5z = -10
...x +5z = 6
---------------------
-4x = -4 *(-1)
4x = 4
x = 4/4
x = 1

x + z = 2
1 + z = 2
z = 2 - 1
z = 1

x + y + z = 2
1 + y + 1 = 2
2 + y = 2
y = 2 - 2
y = 0 

S: {x, y, z} = {1, 0, 1}


8 0
3 years ago
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