Ask question

Ask question

All categories

3 years ago

6

there are 5 walnut trees currently in the park park workers will plant 8 more walnut trees today how many walnut trees will the

park have when the workers are finished

1 answer:

Salsk061 [2.6K]3 years ago

8 0

Answer:13

Step-by-step explanation:

You might be interested in

Applying Inverse Properties In Exercise,apply the inverse properties of logarithmic and exponential functions to simplify the ex

kodGreya [7K]

Answer:

The simplified form of the given expression is (2x-1).

Step-by-step explanation:

Consider the given expression is

$\ln e^{2x-1}$

According to the Inverse Properties of In

$\ln e^x=x$

In the given expression the power of e is (2x-1).

Using the Inverse Properties of In, we get

$2x-1$

Therefore, the simplified form of the given expression is (2x-1).

5 0

3 years ago

Round to the nearest hundreth

n200080 [17]

Answer:

∠ B ≈ 66.42°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos B = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{2}{5}$ , thus

B = $cos^{-1}$ ( $\frac{2}{5}$ ) ≈ 66.42° ( to the nearest hundredth )

3 0

3 years ago

Write an expression to represent:<br> Eight more than the product of two and a number number x

NARA [144]

Eight more than the product of two and a number x

8+2x <== in mathematical form

Eight more= 8+

Product= multiply

number=x

~'Manda

7 0

3 years ago

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

3 years ago

Can ya'll Identify the unit rate in the graph

Alex Ar [27]

Answer:

1 to 0.99 cents

Step-by-step explanation:

Always look for the number one and compare it to the other number and that is usually the unit rate.

7 0

3 years ago