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liq [111]
3 years ago
11

If you have 5 apples on 1 branch how many are there on 5 branches?

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

1st branch = 5

2nd branch =5

3rd branch =5

4th branch = 5

5th branch =5

if u add it all up you get 25 and that's your answer

another simpler way is to say 5 multiplied by 5 = 25.

Hope it helps:)

Step-by-step explanation:

Fofino [41]3 years ago
3 0

Answer: 25 apples

Step-by-step explanation: because 5 apples times 5 branches is 25

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If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

4 0
3 years ago
Read 2 more answers
If c(x) = 4x-2 and d(x) = x^2 + 5x is is (c•d) (x)
FinnZ [79.3K]
<h3>Answer: (c * d)(x) = 4x^3 + 18x^2 - 10x</h3>

Work Shown:

I'm assuming the dot means multiplication. If so, then,

(c * d)(x) = c(x)*d(x)

(c * d)(x) = [ c(x) ] * [ d(x) ]

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(c * d)(x) = 4x(x^2+5x) - 2(x^2+5x) ... distribute

(c * d)(x) = 4x(x^2)+4x(5x) - 2(x^2)-2(5x) ... distribute again

(c * d)(x) = 4x^3 + 20x^2 - 2x^2 - 10x

(c * d)(x) = 4x^3 + 18x^2 - 10x

3 0
2 years ago
R2+2r-33=0 solve by completing the square
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R^2+2r-33=0  move constant to other side by adding 33 to both sides

r^2+2r=33   halve the linear coefficient, square it and add to both sides, in this case it is just one

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(r+1)^2=34  take the square root of both sides...

r+1=34^(1/2)  subtract 1 from both sides

r=-1+34^(1/2) and -1-34^(1/2)
8 0
3 years ago
Martin lifted weights in the gym, Monday thru Friday, for 20 weeks. each day he did 25 repetitions. how many repetitions did he
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Answer:

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