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Neko [114]
4 years ago
15

In a certain study comma the chances of encountering a car crash on the road are stated as ​"1 in 20​." Express the indicated de

gree of likelihood as a probability value between 0 and 1 inclusive. The probability is nothing. ​(Round to three decimal places as​needed.)
Mathematics
1 answer:
Murljashka [212]4 years ago
7 0

Answer:

The probability is 0.05.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In a certain study comma the chances of encountering a car crash on the road are stated as ​"1 in 20​."

This means that in 20 times you go out on the road, in 1 of them you are expected to encounter a car crash.

This means that

p = \frac{1}{20} = 0.05

The probability is 0.05.

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The table below shows some inputs and outputs of the invertible function f with domain all real numbers.
Ratling [72]

Answer:

{f}^{ - 1} (f(93)) = 93

f(f(7)) =  - 15

Step-by-step explanation:

A function and its inverse has the following properties

{f}^{ - 1} (f(x)) = x

This implies that;

{f}^{ - 1} (f(93)) = 93

From the table,

f(7) =  - 6

This means that:

f(f(7)) = f( - 6)

f(f(7)) =  - 15

Note that: f(7) means the value of f(x) when x=7.

From the table f(x)=-6 when x=7.

That is why f(7)=-6.

5 0
3 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

The random variable is μ1 - μ2 = difference in the mean of the employed and unemployed students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
Find the next number in the sequence 1, 1/4, 1/9 , 1/16, 1/25
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(Add5) 1/9..(add 7) 1/16... (add9) 1/25... (add 11) and get -> 1/36
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Would the graph of the following function be discrete or continuous? <br><br> y = 15 + 3x
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The other person is right
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Which equation are you talking about
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