Nice and simple. I'll explain it to you, not just give the answer.
Now, 20 shares = 2980, lets make shares = x, which means it turns to
20x = $2980
Now, you'd simply solve for X, which is done by dividing 2980 by 20, which gets you
x = 149 (cost of one share)
Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+
= ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. This matrix requires for the matrices to be multiplied first, then added.
+
= ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. Here we can add the last 2 matrices to find x.
+
= ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Hope this helps! (Please consider giving brainliest)
Answer:
2 2/3 as an improper fraction is 8/3
8/3 × 1/4 = 2/3
Answer:
P=2.25x-----------1
M=2.25y----------2
Step-by-step explanation:
Step one:
given data
we are told that the cost of pears= $2.25 each
and cost of mango= $2.25 each
Step two:
the chef bought x pears and y mangoes
let the total cost of pears be P
and for mango be M
P=2.25x-----------1
M=2.25y----------2
Answer:
B
Step-by-step explanation: