Slope: 5
y-intercept: (0, -2)
-d has to be 3
think of it as an inverse operation. d is equal to -3 while -d is equal to 3
We know that
cos a+cos b=cos[(a+b)/2]*cos[(a-b)/2]
we have
<span>cos(π/7)+cos(2π/7)+cos(3π/7)+cos(4π/7)-------------> equation 1
</span>cos(4π/7)+cos(2π/7)=cos[(4π/7+2π/7)/2]*cos[(4π/7-2π/7)/2]
=cos(3π/7)*cos(π/7)
then
cos(4π/7)+cos(2π/7)=cos(3π/7)*cos(π/7)--------------> equation 2
[cos(3π/7)+cos(π/7)]=cos[(3π/7+π/7)/2]*cos[(3π/7-π/7)/2]
=cos(2π/7)*cos(π/7)
then
[cos(3π/7)+cos(π/7)]=cos(2π/7)*cos(π/7)-----------> equation 3
I substitute 2 and 3 in 1
[cos(3π/7)+cos(π/7)]+[cos(4π/7)+cos(2π/7)]
{cos(2π/7)*cos(π/7}+{cos(3π/7)*cos(π/7)}
=cos(π/7)*[cos(2π/7)+cos(3π/7)]
the answer is
cos(π/7)+cos(2π/7)+cos(3π/7)+cos(4π/7)=cos(π/7)*[cos(2π/7)+cos(3π/7)]
Answer:
y = 1/2sin(x) - 2
Step-by-step explanation:
Since 2 is subtracted from the end of the function, the graph will be shifted down 2 units. The parent function y = sin(x) goes through the origin, (0, 0); this means the y-intercept of this graph will be at (0, -2).
Additionally, since the function has been stretched horizontally, we know it has been multiplied by a fraction. This means it must be y = 1/2sin(x) - 2.
The first one is D and the second one is D