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sweet [91]
3 years ago
15

What’s 6 I don’t get it need answers fast and 7 can anyone help?!

Mathematics
1 answer:
kirza4 [7]3 years ago
5 0

Answer:

I would go with letter F because it's most reasonable.

Step-by-step explanation:

Each row has 4 squares.

Since three are circled it is 3/4.

So 3/4 divided by 4 is 3/16.

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Can anyone help me with the rest of my ixl m.1 please and thank you
mina [271]

Answer:

u=54

Step-by-step explanation:

VX is middle line of triangle, so

VX=ZY/2.....(1)

We know that

Zy=u

Vx=u-27

Put that in (1) we have:

u-27=u/2

2u-54=u

2u-u=54

u=54

5 0
3 years ago
Monica drinks 0.125 liters of milk during breakfast and 0.20 liters of milk after dinner everyday. Find the total amount of milk
pogonyaev

Answer:

A.  .325L

Step-by-step explanation:

All you have to do is had .125 with .20 to get your answer

4 0
2 years ago
Read 2 more answers
The Gallup Poll uses a procedure called random digit dialing, which creates phone numbers based on a list of all area codes in A
kondaur [170]
Random digit dialing<span> (RDD) is a method for selecting people for involvement in telephone statistical surveys by generating telephone numbers at </span>random<span>. </span>Random digit dialing<span> has the advantage that it includes unlisted numbers that would be missed if the numbers were selected from a phone book.</span>
5 0
3 years ago
Read 2 more answers
A spinner with 9 congruent sections is labeled 1-9. The probability of spinning a 1 or a 9 is 2/9. What is the probability of no
Alecsey [184]

Answer:

7/9 which is the opposite of 2/9

Step-by-step explanation:

3 0
3 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
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