Question

If rt{(x-2)}" alt="f(x) = 2x^2+5\sqrt{(x-2)}" align="absmiddle" class="latex-formula"> complete the following statement:

f(6) = ____

Answer 1

Answer: 82

Simply pug in 6 for $x$

$2(6)^2+5\sqrt{(6-2)} \\72+5\sqrt{4} \\72+5(2)\\72+10=\\82$

Hope this helps and have a great day!!!

$Sofia$

Answer 2

For this case we have a function of the form $y = f (x).$

Where:$f (x) = 2x ^ 2 + 5 \sqrt {x-2}$

We must find the value of the function when x = 6, that is, f (6):

Then, replacing the value of "x"$f (6) = 2 (6) ^ 2 + 5 \sqrt {6-2}\\f (6) = 2 * 36 + 5 \sqrt {4}\\f (6) = 72 + 5 (2)\\f (6) = 72 + 10\\f (6) = 82$

So, $f (6) = 82$

ANswer:

$f (6) = 82$